Tallon Griekspoor def. Alexander Zverev 6(3)-7(7), 6-2, 6-4 — Canadian Open 2026 R64

Match recap

Tallon Griekspoor defeated Alexander Zverev 6(3)-7(7), 6-2, 6-4 in the R64 of the Canadian Open 2026.

Break-point arithmetic decided it. Tallon Griekspoor pried open nine break chances to Alexander Zverev's one and cashed four, flipping a match the betting market had priced 83 percent toward the top seed. After dropping the opening tiebreak, the ATP No. 67 broke three times in the second set, and when Zverev broke for 4-4 in game 8 of the third, Griekspoor broke straight back in game 9 for 5-4 and served out the upset in 2 hours, 34 minutes. He had come in 1-7 on record against the ATP No. 2 — the lone win, at Indian Wells last year, also came from a set down — and the Canadian Open loses its No. 1 seed before the Round of 32.

Match stats

Alexander Zverev: 10 aces, 21 winners, 69% first serves, 4 double faults, 1/1 break points. Tallon Griekspoor: 8 aces, 35 winners, 69% first serves, 2 double faults, 4/9 break points.

Profiles: Alexander Zverev · Tallon Griekspoor — Canadian Open 2026

Head-to-head

Alexander Zverev and Tallon Griekspoor have met 10 times, with Alexander Zverev leading the head-to-head 7–2.

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