Tallon Griekspoor defeated Alexander Zverev 4-6, 7(7)-6(5), 7(7)-6(4) in the R64 of the Indian Wells 2025.
Alexander Zverev: 6 aces, 32 winners, 62% first serves, 2 double faults, 5/14 break points. Tallon Griekspoor: 10 aces, 39 winners, 67% first serves, 9 double faults, 4/9 break points.
Profiles: Alexander Zverev · Tallon Griekspoor — Indian Wells 2025
Alexander Zverev and Tallon Griekspoor have met 10 times, with Alexander Zverev leading the head-to-head 7–2.
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