Alexander Zverev defeated Christopher O'Connell 6-4, 6-4 in the R64 of the Indian Wells 2024.
Alexander Zverev: 3 aces, 23 winners, 57% first serves, 3 double faults, 3/9 break points. Christopher O'Connell: 7 aces, 20 winners, 50% first serves, 2 double faults, 1/6 break points.
Profiles: Alexander Zverev · Christopher O'Connell — Indian Wells 2024
Alexander Zverev and Christopher O'Connell have met 3 times, with Alexander Zverev leading the head-to-head 2–1.
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