Alexander Zverev defeated Tallon Griekspoor 7(9)-6(7), 6-3 in the R32 of the Indian Wells 2024.
Alexander Zverev: 8 aces, 22 winners, 76% first serves, 1 double fault, 3/8 break points. Tallon Griekspoor: 8 aces, 20 winners, 68% first serves, 6 double faults, 1/3 break points.
Profiles: Alexander Zverev · Tallon Griekspoor — Indian Wells 2024
Alexander Zverev and Tallon Griekspoor have met 10 times, with Alexander Zverev leading the head-to-head 7–2.
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