Tallon Griekspoor defeated Botic Van De Zandschulp 6-4, 6-4, 6-4 in the R64 of the Australian Open 2023.
Tallon Griekspoor: 9 aces, 32 winners, 72% first serves, 2 double faults, 4/5 break points. Botic Van De Zandschulp: 8 aces, 20 winners, 64% first serves, 2 double faults, 1/4 break points.
Profiles: Tallon Griekspoor · Botic Van De Zandschulp — Australian Open 2023
Tallon Griekspoor and Botic Van De Zandschulp have met 3 times, with Tallon Griekspoor leading the head-to-head 2–0.
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