Thanasi Kokkinakis faced Terence Atmane in the R128 of French Open (Roland-Garros) 2026 at Paris on May 25, 2026. Thanasi Kokkinakis won 6(5)-7(7) 6-2 4-6 6-3 7-5.
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Thanasi Kokkinakis clawed past Terence Atmane 6(5)-7 6-2 4-6 6-3 7-5 in a four-hour-plus French Open opener, dropping a tight first-set tiebreak before grinding the Frenchman down on serve. Kokkinakis fired 24 aces and converted five of 16 break points — volume over efficiency — while Atmane managed just 2-of-6 on his own break chances, the gap that ultimately decided a deciding set fought to 7-5.